63r^2+20r-3=

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Solution for 63r^2+20r-3= equation:


Simplifying
63r2 + 20r + -3 = 0

Reorder the terms:
-3 + 20r + 63r2 = 0

Solving
-3 + 20r + 63r2 = 0

Solving for variable 'r'.

Factor a trinomial.
(-3 + -7r)(1 + -9r) = 0

Subproblem 1

Set the factor '(-3 + -7r)' equal to zero and attempt to solve: Simplifying -3 + -7r = 0 Solving -3 + -7r = 0 Move all terms containing r to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -7r = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -7r = 0 + 3 -7r = 0 + 3 Combine like terms: 0 + 3 = 3 -7r = 3 Divide each side by '-7'. r = -0.4285714286 Simplifying r = -0.4285714286

Subproblem 2

Set the factor '(1 + -9r)' equal to zero and attempt to solve: Simplifying 1 + -9r = 0 Solving 1 + -9r = 0 Move all terms containing r to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -9r = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -9r = 0 + -1 -9r = 0 + -1 Combine like terms: 0 + -1 = -1 -9r = -1 Divide each side by '-9'. r = 0.1111111111 Simplifying r = 0.1111111111

Solution

r = {-0.4285714286, 0.1111111111}

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